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authorLukas Fleischer <calcurse@cryptocrack.de>2013-05-04 17:11:33 +0200
committerLukas Fleischer <calcurse@cryptocrack.de>2013-05-04 20:32:26 +0200
commitce93fa8adbeb31d160cba198e50e3f828e8def50 (patch)
tree8380e143ab3fec663f284a9e6d958996c2561b75 /src/calcurse.h
parent370c4031be9c921ae54ccb7cafff71d0a2c9b790 (diff)
downloadcalcurse-ce93fa8adbeb31d160cba198e50e3f828e8def50.zip
Use a macro to determine the size of arrays
Use following macro instead of "sizeof(x) / sizeof(x[0])" everywhere: #define ARRAY_SIZE(x) (sizeof(x) / sizeof((x)[0])) Signed-off-by: Lukas Fleischer <calcurse@cryptocrack.de>
Diffstat (limited to 'src/calcurse.h')
-rw-r--r--src/calcurse.h2
1 files changed, 2 insertions, 0 deletions
diff --git a/src/calcurse.h b/src/calcurse.h
index 1dfd648..da1f447 100644
--- a/src/calcurse.h
+++ b/src/calcurse.h
@@ -230,6 +230,8 @@
#define UTF8_ISCONT(ch) ((unsigned char)ch >= 0x80 && \
(unsigned char)ch <= 0xBF)
+#define ARRAY_SIZE(x) (sizeof(x) / sizeof((x)[0]))
+
#define MAX(x,y) ((x)>(y)?(x):(y))
#define MIN(x,y) ((x)<(y)?(x):(y))