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/*
* Copyright (c) 2020, Stephan Unverwerth <s.unverwerth@serenityos.org>
* Copyright (c) 2021-2022, David Tuin <davidot@serenityos.org>
*
* SPDX-License-Identifier: BSD-2-Clause
*/
#include <AK/StringView.h>
#include <AK/Vector.h>
#include <LibJS/ParserError.h>
#include <LibJS/Token.h>
namespace JS {
ErrorOr<String> ParserError::to_string() const
{
if (!position.has_value())
return String::from_deprecated_string(message);
return String::formatted("{} (line: {}, column: {})", message, position.value().line, position.value().column);
}
DeprecatedString ParserError::to_deprecated_string() const
{
if (!position.has_value())
return message;
return DeprecatedString::formatted("{} (line: {}, column: {})", message, position.value().line, position.value().column);
}
DeprecatedString ParserError::source_location_hint(StringView source, char const spacer, char const indicator) const
{
if (!position.has_value())
return {};
// We need to modify the source to match what the lexer considers one line - normalizing
// line terminators to \n is easier than splitting using all different LT characters.
DeprecatedString source_string = source.replace("\r\n"sv, "\n"sv, ReplaceMode::All).replace("\r"sv, "\n"sv, ReplaceMode::All).replace(LINE_SEPARATOR_STRING, "\n"sv, ReplaceMode::All).replace(PARAGRAPH_SEPARATOR_STRING, "\n"sv, ReplaceMode::All);
StringBuilder builder;
builder.append(source_string.split_view('\n', SplitBehavior::KeepEmpty)[position.value().line - 1]);
builder.append('\n');
for (size_t i = 0; i < position.value().column - 1; ++i)
builder.append(spacer);
builder.append(indicator);
return builder.to_deprecated_string();
}
}
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