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## Name
basename - extract file name from a path
## Synopsis
```**c++
#include <libgen.h>
char* basename(char* path);
```
## Description
Given a file path, `basename()` returns that file's name. `basename()` works
purely lexically, meaning it only manipulates the path as a string, and does
not check if such a file actually exists.
A call to `basename()` may reuse and modify the passed in `path` buffer. Do not
expect it to have the same value after calling `basename()`.
## Return value
`basename()` returns the file name as a string. This string may be allocated
in static memory, or it may point to some part of the original `path` buffer.
Do not `free()` the returned string, and do not `free()` the original `path`
buffer while using the returned string.
## Examples
```c++
#include <AK/LogStream.h>
#include <libgen.h>
int main()
{
char path1[] = "/home/anon/README.md";
dbgln("{}", basename(path1)); // should be "README.md"
char path2[] = "foo/bar/";
dbgln("{}", basename(path2)); // should be "bar"
char path3[] = "foo";
dbgln("{}", basename(path3)); // should be "foo"
char path4[] = "/";
dbgln("{}", basename(path4)); // should be "/"
}
```
## See also
* [`dirname`(3)](dirname.md)
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