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The existing InputBitStream methods only read in little endian, as this
is what the rest of the system requires. Two new methods allow the input
bitstream to read bits in big endian as well, while using the existing
state infrastructure.
Note that it can lead to issues if little endian and big endian reads
are used out of order without aligning to a byte boundary first.
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SPDX License Identifiers are a more compact / standardized
way of representing file license information.
See: https://spdx.dev/resources/use/#identifiers
This was done with the `ambr` search and replace tool.
ambr --no-parent-ignore --key-from-file --rep-from-file key.txt rep.txt *
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In the case that both the stream and the wrapped substream had errors
to be handled only one of the two would be resolved due to boolean
short circuiting. this commit ensures both are handled irregardless
of one another.
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This ensures that when a DeflateCompressor stream is cleared of any
errors its underlying wrapped streams (InputBitStream/InputMemoryStream)
will be cleared as well and wont fail a VERIFY on destruction.
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If the bit write is aligned (or has been aligned during the write) we can
write in multiples of 32/16/8 bits for increased performance.
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This will be used in the deflate compressor.
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Consider the following snippet:
void foo(InputStream& stream) {
if(!stream.eof()) {
u8 byte;
stream >> byte;
}
}
There is a very subtle bug in this snippet, for some input streams eof()
might return false even if no more data can be read. In this case an
error flag would be set on the stream.
Until now I've always ensured that this is not the case, but this made
the implementation of eof() unnecessarily complicated.
InputFileStream::eof had to keep a ByteBuffer around just to make this
possible. That meant a ton of unnecessary copies just to get a reliable
eof().
In most cases it isn't actually necessary to have a reliable eof()
implementation.
In most other cases a reliable eof() is avaliable anyways because in
some cases like InputMemoryStream it is very easy to implement.
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The streaming operator doesn't short-circuit, consider the following
snippet:
void foo(InputStream& stream) {
int a, b;
stream >> a >> b;
}
If the first read fails, the second is called regardless. It should be
well defined what happens in this case: nothing.
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